To divide a line segment BC internally in the ratio 3 : 5, we draw a ray BX such that ∠CBX is an acute angle. What will be the minimum number of points to be located at equal distances, on ray BX?
Last updated at Oct. 21, 2020 by Teachoo
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Question 12 To divide a line segment BC internally in the ratio 3 : 5, we draw a ray BX such that ∠CBX is an acute angle. What will be the minimum number of points to be located at equal distances, on ray BX? So, minimum number of points are 8 So, minimum number of points are 8 1 marks
CBSE Class 10 Sample Paper for 2021 Boards - Maths Basic
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CBSE Class 10 Sample Paper for 2021 Boards - Maths Basic
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